$Id: cos_forward.omh 2506 2012-10-24 19:36:49Z bradbell $
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CppAD: C++ Algorithmic Differentiation: Copyright (C) 2003-06 Bradley M. Bell

CppAD is distributed under multiple licenses. This distribution is under
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                    Eclipse Public License Version 1.0.

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$begin CosForward$$
$spell
	cos
	Taylor
$$

$index cos, forward theory$$
$index theory, cos forward$$
$index forward, cos theory$$

$section Cosine Function Forward Taylor Polynomial Theory$$

If $latex F(x) = \cos(x) $$ 
$latex \[
	1 * F^{(1)} (x) - 0 * F (x)  = - \sin(x)
\] $$
and in the
$xref/
	ForwardTheory/ 
	Standard Math Functions/ 
	Differential Equation/
	standard math function differential equation/
	1
/$$,
$latex A(x) = 0$$,
$latex B(x) = 1$$,
and $latex D(x) = - \sin(x)$$.
We use $latex a$$, $latex b$$, $latex d$$, $latex s$$
and $latex z$$ to denote the 
Taylor coefficients for
$latex A [ X (t) ] $$, 
$latex B [ X (t) ]$$, 
$latex D [ X (t) ] $$,
$latex \sin [ X(t) ]$$,
and $latex F [ X(t) ] $$ respectively.
It now follows from the general
$xref/
	ForwardTheory/
	Standard Math Functions/
	Taylor Coefficients Recursion Formula/
	Taylor coefficients recursion formula/
	1
/$$
that for $latex j = 0 , 1, \ldots$$,
$latex \[
\begin{array}{rcl}
z^{(0)} & = & \cos ( x^{(0)} )
\\
e^{(j)} 
& = & d^{(j)} + \sum_{k=0}^{j} a^{(j-k)} * z^{(k)}
\\
& = & -s^{(j)}
\\
z^{(j+1)} & = & \frac{1}{j+1} \frac{1}{ b^{(0)} } 
\left(
	\sum_{k=1}^{j+1} k x^{(k)} e^{(j+1-k)} 
	- \sum_{k=1}^j k z^{(k)}  b^{(j+1-k)} 
\right)
\\
& = & - \frac{1}{j+1} 
	\sum_{k=1}^{j+1} k x^{(k)} s^{(j+1-k)} 
\end{array}
\] $$ 
Using $latex c$$ for the Taylor coefficients of $latex \cos[ X(t) ]$$
the order $latex j+1$$ coefficient can be generated using the
lower order coefficients for $latex \sin[ X(t) ]$$ and $latex \cos[ X(t) ]$$
by the following formula:
$latex \[
c^{(j+1)} = - \frac{1}{j+1} 
	\sum_{k=1}^{j+1} k x^{(k)} s^{(j+1-k)} 
\] $$

$end