$Id: exp_reverse.omh 3683 2015-05-10 02:24:16Z bradbell $
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CppAD: C++ Algorithmic Differentiation: Copyright (C) 2003-15 Bradley M. Bell

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$begin exp_reverse$$
$spell
	Taylor
	exp
	expm
$$

$section Exponential Function Reverse Mode Theory$$
$mindex exp, expm1$$

We use the reverse theory
$cref%standard math function
	%ReverseTheory
	%Standard Math Functions
%$$
definition for the functions $latex H$$ and $latex G$$.
The zero order forward mode formula for the
$cref/exponential/exp_forward/$$ is
$latex \[
	z^{(0)}  =  F ( x^{(0)} )
\] $$
and for $latex j > 0$$,
$latex \[
	z^{(j)}  = x^{(j)} d^{(0)}
		+ \frac{1}{j} \sum_{k=1}^{j} k x^{(k)} z^{(j-k)}
\] $$
where
$latex \[
d^{(0)} = \left\{ \begin{array}{ll}
	0 & \R{if} \; F(x) = \R{exp}(x)
	\\
	1 & \R{if} \; F(x) = \R{expm1}(x)
\end{array} \right.
\] $$
For order $latex j = 0, 1, \ldots$$ we note that
$latex \[
\begin{array}{rcl}
\D{H}{ x^{(j)} }
& = & \D{G}{ x^{(j)} }  + \D{G}{ z^{(j)} } \D{ z^{(j)} }{ x^{(j)} }
\\
& = & \D{G}{ x^{(j)} }  + \D{G}{ z^{(j)} } ( d^{(0)} + z^{(0)} )
\end{array}
\] $$

If $latex j > 0$$, then for $latex k = 1 , \ldots , j$$
$latex \[
\begin{array}{rcl}
\D{H}{ x^{(k)} } & = &
\D{G}{ x^{(k)} }  + \D{G}{ z^{(j)} } \frac{1}{j}  k z^{(j-k)}
\\
\D{H}{ z^{(j-k)} } & = &
\D{G}{ z^{(j-k)} }  + \D{G}{ z^{(j)} } \frac{1}{j}  k x^{(k)}
\end{array}
\] $$

$end